[(x)(x)]+11x=12

Solution for [(x)(x)]+11x=12 equation:

Simplifying
[(x)(x)] + 11x = 12

Multiply x * x
[x2] + 11x = 12
x2 + 11x = 12

Reorder the terms:
11x + x2 = 12

Solving
11x + x2 = 12

Solving for variable 'x'.

Reorder the terms:
-12 + 11x + x2 = 12 + -12

Combine like terms: 12 + -12 = 0
-12 + 11x + x2 = 0

Factor a trinomial.
(-12 + -1x)(1 + -1x) = 0

Subproblem 1
Set the factor '(-12 + -1x)' equal to zero and attempt to solve:

Simplifying
-12 + -1x = 0

Solving
-12 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '12' to each side of the equation.
-12 + 12 + -1x = 0 + 12

Combine like terms: -12 + 12 = 0
0 + -1x = 0 + 12
-1x = 0 + 12

Combine like terms: 0 + 12 = 12
-1x = 12

Divide each side by '-1'.
x = -12

Simplifying
x = -12
Subproblem 2
Set the factor '(1 + -1x)' equal to zero and attempt to solve:

Simplifying
1 + -1x = 0

Solving
1 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1x = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1x = 0 + -1
-1x = 0 + -1

Combine like terms: 0 + -1 = -1
-1x = -1

Divide each side by '-1'.
x = 1

Simplifying
x = 1
Solution
x = {-12, 1}